Practice question

**Inductive reactance calculation** for 60 mH, 50 Hz, X_L=2π×50×0.06=18.85 Ω, V_rms=220 V, I_rms=220/18.85=11.67 A, for 70 mH, 50 Hz, X_L=21.99 Ω, I=110/21.99=5 A, showing X_L ∝ f L, higher f or L increases opposition. Peak voltage: v_m = 300 V . RMS voltage: V = (v_m/√(2)) = (300/1.414) ≈ 212.1 V . RMS current: I = (V/R) = (212.1/150) ≈ 1.414 A . Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms = V_rms/Z, P = V_rms I_rms cosφ, V_s/V_p = N_s/N_p, calculation gives 1.414 A, consistent with phasor analysis and resonance condition X_L = X_C.