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#tension

25 public questions tagged with this topic.

Doppler Effect

A string of length 4 m and mass 0.08 kg is under a tension of 200 N. How long does a transverse pulse take to travel its

**Doppler effect** describes apparent frequency shift due to relative motion between source and observer, f' = f·v/(v ∓ v_s) for source motion, f' = f·(v ± v_o)/v for observer motion, upper signs for approach increasing observed frequency. Motion towards observer compresses wavelength raising f'. Linear mass density: μ = (0.08/4) = 0.02 kg/m . Speed: v = √((T/μ)) = √((200/0.02)) = √(10000) = 100 m/s . Time: t = (length/v) = (4/100) = 0.04 s . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 0.04 s, illustrating frequency-length-speed interdepen

Ref: NCERT > Physics Book > Waves > Doppler Effect

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Doppler Effect

A transverse wave on a string has a tension of 180 N and a linear mass density of 0.03 kg/m. What is the wavelength if t

**Relative motion** changes effective wavelength encountered. For moving source approaching stationary observer, wavelength ahead λ' = (v - v_s)/f, so f' = v/λ' = f·v/(v - v_s) > f, basis for calculating apparent pitch shift in sound. Speed: v = √((T/μ)) = √((180/0.03)) = √(6000) ≈ 77.46 m/s . Wavelength: λ = (v/v) = (77.46/20) ≈ 3.87 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 3.87 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

Ref: NCERT > Physics Book > Waves > Doppler Effect

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Superposition and Interference of Waves

A transverse wave on a string has a tension of 144 N and a linear mass density of 0.016 kg/m. What is the wavelength if

**Wave addition** governed by phase difference determines resultant intensity ∝ A². Phase arises from path difference Δ = (2π/λ)·Δx, and resultant formula captures interference condition quantitatively for NCERT problems. Speed: v = √((T/μ)) = √((144/0.016)) = √(9000) ≈ 94.87 m/s . Wavelength: λ = (v/v) = (94.87/15) ≈ 6.32 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 6.32 m, illustrating frequency-length-speed interdependence and quantization by boundaries. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry an

Ref: NCERT > Physics Book > Waves > Superposition and Interference of Waves

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Wave Speed, Energy and Power

A transverse wave travels on a string with a tension of 200 N and linear mass density of 0.025 kg/m. What is the wavelen

**Energy transport** in waves scales with amplitude squared A² and frequency squared ω². Wave speed determines propagation rate, and understanding T and μ allows quantitative prediction of v and associated frequencies. Speed: v = √((T/μ)) = √((200/0.025)) = √(8000) ≈ 89.4 m/s . Wavelength: λ = (v/v) = (89.4/40) ≈ 2.24 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 2.24 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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Wave Speed, Energy and Power

A transverse wave on a string has a tension of 120 N and a linear mass density of 0.015 kg/m. What is the wavelength if

**Wave speed on string** is v = √(T/μ), T tension (N), μ = m/L linear mass density (kg/m). Higher T increases restoring force raising speed, heavier μ lowers speed. Frequency follows f = v/λ, linking mechanical properties to wave dynamics and harmonic series. Speed: v = √((T/μ)) = √((120/0.015)) = √(8000) ≈ 89.44 m/s . Wavelength: λ = (v/v) = (89.44/50) ≈ 1.79 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 1.8 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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Wave Speed, Energy and Power

A transverse wave travels on a string with tension 400 N and linear mass density 0.1 kg/m. What is the speed of the wave

**Energy transport** in waves scales with amplitude squared A² and frequency squared ω². Wave speed determines propagation rate, and understanding T and μ allows quantitative prediction of v and associated frequencies. Speed: v = √((T/μ)) = √((400/0.1)) = √(4000) ≈ 63.25 m/s . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 63.2 m/s, illustrating frequency-length-speed interdependence and quantization by boundaries. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry and dimensional consistency useful for CBSE, NEET a

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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Wave Speed, Energy and Power

A string of length 2.5 m and mass 0.05 kg has a wave speed of 100 m/s. What is the tension in the string?

**Energy transport** in waves scales with amplitude squared A² and frequency squared ω². Wave speed determines propagation rate, and understanding T and μ allows quantitative prediction of v and associated frequencies. μ = (0.05/2.5) = 0.02 kg/m . v = √((T/μ)) ⇒ 100 = √((T/0.02)) ⇒ 100² = (T/0.02) . T = 10000 × 0.02 = 200 N . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 200 N, illustrating frequency-length-speed interdependence and quantization by boundaries.

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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Wave Speed, Energy and Power

A transverse wave on a string has a tension of 200 N and a linear mass density of 0.04 kg/m. What is the wavelength if t

**Energy transport** in waves scales with amplitude squared A² and frequency squared ω². Wave speed determines propagation rate, and understanding T and μ allows quantitative prediction of v and associated frequencies. Speed: v = √((T/μ)) = √((200/0.04)) = √(5000) ≈ 70.71 m/s . Wavelength: λ = (v/v) = (70.71/25) ≈ 2.83 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 2.83 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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Wave Speed, Energy and Power

A transverse wave on a string has a tension of 90 N and a linear mass density of 0.01 kg/m. What is the frequency if the

**Transverse wave velocity** depends on medium not frequency alone. For string under tension, v ∝ √(T/μ), calculation requires μ from mass and length, then square root evaluation, giving v in m/s, then f = v/λ for given wavelength. Speed: v = √((T/μ)) = √((90/0.01)) = √(9000) ≈ 94.87 m/s . Frequency: v = (v/λ) = (94.87/1.5) ≈ 63.25 Hz . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 63 Hz, illustrating frequency-length-speed interdependence and quantization by boundaries.

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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Transverse and Longitudinal Waves

A steel wire of length 4 m and mass 0.08 kg is under tension. If a transverse wave takes 0.02 s to travel its length, wh

**Wave classification** depends on particle vibration relative to propagation. Longitudinal waves have particle oscillation parallel to propagation, creating compressions and rarefactions as in sound in air; transverse have perpendicular oscillation. Tuning fork generates longitudinal sound because air cannot sustain shear. Speed: v = (length/time) = (4/0.02) = 200 m/s . μ = (0.08/4) = 0.02 kg/m . v = √((T/μ)) ⇒ 200 = √((T/0.02)) ⇒ 200² = (T/0.02) . T = 40000 × 0.02 = 800 N . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 800 N, illustrating

Ref: NCERT > Physics Book > Waves > Transverse and Longitudinal Waves

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Wave Speed, Energy and Power

A transverse wave travels on a string with tension 250 N and linear mass density 0.05 kg/m. What is the speed of the wav

**Energy transport** in waves scales with amplitude squared A² and frequency squared ω². Wave speed determines propagation rate, and understanding T and μ allows quantitative prediction of v and associated frequencies. Speed: v = √((T/μ)) = √((250/0.05)) = √(5000) ≈ 70.71 m/s . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 70.7 m/s, illustrating frequency-length-speed interdependence and quantization by boundaries. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry and dimensional consistency useful for CBSE, NEET

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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Wave Speed, Energy and Power

What happens to the speed of a transverse wave on a string if the tension is doubled while keeping the linear mass densi

**Wave speed on string** is v = √(T/μ), T tension (N), μ = m/L linear mass density (kg/m). Higher T increases restoring force raising speed, heavier μ lowers speed. Frequency follows f = v/λ, linking mechanical properties to wave dynamics and harmonic series. The speed of a transverse wave is v = √((T/μ)) . If tension T doubles, v' = √((2T/μ)) = √(2) × v , increasing by a factor of √(2) (approximately 1.414). Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields Increases by a factor of √(2), illustrating frequency-length-speed interdependence and q

Ref: NCERT > Physics Book > Waves > Wave Speed, Energy and Power

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