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#standing force

2 public questions tagged with this topic.

Universal Law of Gravitation

A 55kg person stands on two bones, each with area 14cm2. What is the average pressure on the bones? (Take g\=10m/s2)

Pav = FA, F = mg = 55×10 = 550N. Total area A = 2×14×10−4 = 2.8×10−3m2. Pav = 5502.8×10−3 = 1.964×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.96 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Universal Law of Gravitation

A 75kg person stands on two bones, each with area 24cm2. What is the average pressure on the bones? (Take g\=9.8m/s2)

Pav = FA, F = mg = 75×9.8 = 735N. Total area A = 2×24×10−4 = 4.8×10−3m2. Pav = 7354.8×10−3 = 1.53125×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.53 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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