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#drag force calculation

2 public questions tagged with this topic.

A sphere of radius 0.035m moves at 0.09m/s through glycerine (η\=0.83Pa s). What is the viscous drag force?

Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.035m, v = 0.09m/s. F = 6×3.14×0.83×0.035×0.09 = 0.0493N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.05 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A sphere of radius 0.045m moves at 0.15m/s through machine oil (η\=0.034Pa s). What is the viscous drag force?

Stokes’ law: F = 6πηav. η = 0.034Pa s, a = 0.045m, v = 0.15m/s. F = 6×3.14×0.034×0.045×0.15 = 0.0433N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.043 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.