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Question

Why is the electric field inside a hollow conducting shell zero when no charges are present inside,
regardless of the external field?

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Explanation

**Electrostatic shielding** inside hollow conducting shell field zero when no charges inside, regardless of external field, because free charges redistribute on outer surface to cancel external field inside conductor, E=0 inside material in equilibrium, consequence of Gauss's law and conductor property. In electrostatic equilibrium, the electric field inside a conductor is zero. For a hollow conducting shell, charges reside on the surfaces. If no charges are inside, applying Gauss’s law to a surface inside the shell shows no enclosed charge ( oint E · dA = (qₑₙc/ε₀) , qₑₙc = 0 ), so E = 0 inside. External fields induce charges on the outer surface,

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