Practice question
Question
Why does the electric field inside a conductor remain zero when a non-symmetric external field is
applied?
Explanation
**Electrostatic shielding** inside hollow conducting shell field zero when no charges inside, regardless of external field, because free charges redistribute on outer surface to cancel external field inside conductor, E=0 inside material in equilibrium, consequence of Gauss's law and conductor property. In electrostatic equilibrium, the electric field inside a conductor must be zero, regardless of the external field’s symmetry. Free charges redistribute on the conductor’s surface to cancel the external field inside. For a non-symmetric field, the surface charge distribution adjusts accordingly—more charges where the field is stronger and fewer where weaker—ensuring the net field inside is zero, as any internal field would cause charge
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.