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Question

What is the path difference for the third dark fringe in a double-slit experiment?

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Explanation

**Convex lens focusing** plane wave into point because lens introduces phase delay proportional to thickness, converting plane wavefront to spherical converging to focal point, property ensures rays parallel to axis meet at focus, spherical aberration minimized for paraxial rays, lensmaker's formula determines focal length. Destructive interference occurs at Δ = (n + (1/2))λ . For the third dark fringe, n = 2 , Δ = (2 + (1/2))λ = (5λ/2) . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC = 1/n, λ' = λ/n and A = 2a cos(φ/2), calculation

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