Practice question
Question
What is the molality of a solution containing 60 g of glucose (molar mass = 180 g/mol) in 540 g of water?
Explanation
Moles of glucose = (60/180) = 0.333 mol . Mass of solvent = 540 g = 0.54 kg. Molality = (0.333/0.54) ≈ 0.617 mol/kg .
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