Practice question
Question
What is the molality of a solution containing 12 g of sucrose (molar mass = 342 g/mol) in 300 g of water?
Explanation
Moles of sucrose = (12/342) ≈ 0.0351 mol . Mass of solvent = 300 g = 0.3 kg. Molality = (0.0351/0.3) ≈ 0.117 mol/kg .
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