Practice question
Question
What is the freezing point depression of a solution containing 9 g of glucose (molar mass = 180 g/mol) in 250 g of water? ( Kf = 1.86 K kg mol⁻¹ )
Explanation
Moles of glucose = (9/180) = 0.05 mol . Molality = (0.05/0.25) = 0.2 mol/kg . Δ Tf = 1.86 × 0.2 = 0.372 K .
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