Practice question
Question
What is the escape speed from a planet with mass 2.7×1024kg and radius 4.5×106m? (G\=6.67×10−11N m2/kg2)
Explanation
ve = 2GMR. ve = 2×6.67×10−11×2.7×10244.5×106. ve = 8.001×107≈8.94×103m/s≈8.9km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.9 km/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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