Practice question
Question
What is the distance of the fifth dark fringe from the central maximum in a double-slit experiment if
\( \lambda = 650 \, \text{nm} \), \( d = 0.5 \, \text{mm} \), and \( D = 1.0 \, \text{m} \)?
Explanation
**Double-slit vs single-slit** double-slit interference pattern has equally spaced bright fringes with envelope due to single-slit diffraction, single-slit central maximum width 2λ D/a, intensity of secondary maxima decreases with order, condition for coherence constant frequency and phase, path difference for bright n λ, dark (n+½)λ. Dark fringe position x_n = ((n + (1/2)) λ D/d) . For the fifth dark fringe, n = 4 . λ = 6.5 × 10⁻⁷ m , d = 5.0 × 10⁻⁴ m , D = 1.0 m . x₄ = ((4 + (1/2)) × 6.5 × 10⁻⁷ × 1.0/5.0 × 10⁻⁴) = (4.5 × 6.5 × 10⁻⁷/5.0 × 10⁻⁴)
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