Skip to content

Question

Water (ρ\=1000kg/m3) flows horizontally at 2.8m/s with pressure 1.9×105Pa. If the speed increases to 5.2m/s, what is the new pressure?

Options

Choose one · Correct answer highlighted

Explanation

Bernoulli’s equation: P1+12ρv12 = P2+12ρv22. P1 = 1.9×105Pa, v1 = 2.8m/s, v2 = 5.2m/s, ρ = 1000kg/m3. P2 = 1.9×105+12×1000(7.84−27.04) = 1.9×105−9600 = 1.804×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.80 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.