Practice question

Given: Two parallel wires 0.11 m apart carry currents of 6 A and 2 A in the same direction. What is the force per unit length between them? ( μ_0 = 4 π × 10⁻⁷T m/A ) These values define the system as per NCERT data. Formula: Force per unit length f = μ_0 I_1 I_2/2 π d. This is standard NCERT relation. Substitution & Calculation: f = frac4 π × 10⁻⁷ × 6 × 22 π × 0.11 = frac48 × 10⁻⁷⁰.22 = 2.18 × 10⁻⁶N/m . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.