Practice question
Question
The solubility of Ag₂CrO₄ is 1.3 × 10⁻⁴ M . What is its Ksp ?
Explanation
For Ag₂CrO₄ <=> 2Ag+ + CrO₄²⁻ , [Ag+] = 2S = 2.6 × 10⁻⁴ , [CrO₄²⁻] = S = 1.3 × 10⁻⁴ . Ksp = (2.6 × 10⁻⁴)² (1.3 × 10⁻⁴) = 8.79 × 10⁻¹² .
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