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Question

The number density of a gas is 2.5 × 10²⁵ m⁻³. If the molecular diameter is 2 × 10⁻¹⁰ m, what is the mean free path?

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Explanation

**Degrees of freedom** f counts independent motions, monatomic 3 translational, diatomic 3 translational +2 rotational =5 at room T, vibrational adds at high T, molar specific heat at constant volume C_v = f/2 R, at constant pressure C_p = C_v + R, ratio γ = C_p/C_v = (f+2)/f, monatomic γ=5/3≈1.67, diatomic γ=7/5=1.4. l = (1)/(√(2) n π d²).n = 2.5 × 10²⁵, d = 2 × 10⁻¹⁰, π ≈ 3.14.l = (1)/(1.414 × 2.5 × 10²⁵) × 3.14 × (2 × 10⁻¹⁰)² = (1)/(4.44 × 10¹⁷) ≈ 2.25 × 10⁻⁷ m . Substituting values gives 2.25 × 10⁻⁷ m, which matches expected kinetic theory result,

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