Practice question
Question
The Ka of a weak acid HX is 2.5 × 10⁻⁵ . What is its pKa ?
Explanation
pKa = -log Ka = -log(2.5 × 10⁻⁵) = 5 - log 2.5 ≈ 5 - 0.398 = 4.6 .
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