Practice question
Question
The¹H NMR spectrum of¹³CH3CI in CDCl₃shows two lines (doublet, 1 :1 intensity} spaced 140 Hz apart. The carbon (¹³C} NMR spectrum of the same molecule shows four lines (quartet, intensity ratio 1:3:3:1 }. Both¹H and ¹³c have nuclear spin quantum numbers I = 1/2. Based on the above information which one of the following options is correct?
Explanation
Analysis of the¹h nmr spectrum of¹³ch3ci in cdcl₃shows two shows The multiplicity pattern observed follows the 2n/+1 rule. represents established outcome. functional assays supports option A, whereas distractors confuse substrate or regulatory direction and fail to reproduce observed results.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.