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Question

The¹H NMR spectrum of¹³CH3CI in CDCl₃shows two lines (doublet, 1 :1 intensity} spaced 140 Hz apart. The carbon (¹³C} NMR spectrum of the same molecule shows four lines (quartet, intensity ratio 1:3:3:1 }. Both¹H and ¹³c have nuclear spin quantum numbers I = 1/2. Based on the above information which one of the following options is correct?

Options

Choose one · Correct answer highlighted

Explanation

Analysis of the¹h nmr spectrum of¹³ch3ci in cdcl₃shows two shows The multiplicity pattern observed follows the 2n/+1 rule. represents established outcome. functional assays supports option A, whereas distractors confuse substrate or regulatory direction and fail to reproduce observed results.

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