Practice question
Question
Let f(x) be a real -valued function such that f'(x₀) = 0 for some x₀ ∈ (0, 1), and f"(x) > 0 for all x ∈ (0, 1). Then f(x) has
Explanation
Applying the basic concept, complete solution: write formula, plug data, do arithmetic. Final value matches exactly one local minimum in (0, 1). Simple and accurate.
Discussion
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