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Question

In Young’s double-slit experiment, if the slit separation is \( 0.25 \, \text{mm} \), the screen is \(
1.0 \, \text{m} \) away, and the fringe width is \( 2.4 \, \text{mm} \), what is the wavelength of
light?

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Explanation

**Diffraction bending** property of light waves causes bending around corners, width of central maximum inversely proportional to slit width, intensity of secondary maxima decreases with order because less constructive interference, angular position of minima θ_n = n λ/a, n=±1,±2..., second minimum n=2, third n=3, condition for third secondary maximum approx a sinθ = (2n+1)λ/2. Fringe width β = (λ D/d) . Given β = 2.4 mm = 2.4 × 10⁻³ m , D = 1.0 m , d = 0.25 mm = 2.5 × 10⁻⁴ m . λ = (β d/D) = (2.4 × 10⁻³ × 2.5 × 10⁻⁴/1.0) = 6.0 × 10⁻⁷ m =

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