Practice question
Question
In a series LCR circuit, under what condition does the circuit behave as if it has only resistance?
Explanation
**Resonance in LCR** occurs when X_L = X_C, ω₀ =1/√(LC), f₀=1/(2π√(LC)), impedance Z=R minimum, current maximum I₀=V/R, circuit behaves as if only resistance because inductive and capacitive voltages equal opposite cancel, net reactance zero, phase φ=0°, power factor 1, current in phase with voltage. In a series LCR circuit, the circuit behaves as purely resistive at resonance, where the inductive reactance equals the capacitive reactance ( X_L = X_C ). This cancels the reactive components, leaving only the resistance to determine the impedance. Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms = V_rms/Z, P = V_rms I_rms cosφ,
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.