Practice question
Question
For the equilibrium X₂(g) <=> 2X(g) , if the initial pressure of X₂ is 2 atm and at equilibrium the total pressure is 3 atm, what is Kp ?
Explanation
Let the pressure of X at equilibrium be 2p , X₂ = 2 - p , total pressure = (2 - p) + 2p = 2 + p = 3 , p = 1 . PX₂ = 1 atm , PX = 2 atm . Kp = ((PX)²/PX₂) = ((2)²/1) = 4 .
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