Practice question
Question
For the equilibrium CO(g) + H₂O(g) <=> CO₂(g) + H₂(g) , if the initial concentrations of CO and H₂O are 0.2 M each and at equilibrium [CO₂] = 0.08 M , what is Kc ?
Explanation
At equilibrium, [CO] = [H₂O] = 0.2 - 0.08 = 0.12 M , [CO₂] = [H₂] = 0.08 M . Thus, Kc = ([CO₂][H₂]/[CO][H₂O]) = ((0.08)²/(0.12)²) = (0.0064/0.0144) ≈ 0.444 .
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