Practice question
Question
For N₂(g) + 2O₂(g) <=> 2NO₂(g), K_c = 0.01 at 500 K. What is K_c for the reverse reaction?
Explanation
Given:
For N₂(g) + 2O₂(g) <=> 2NO₂(g), K_c = 0.01 at 500 K. What is K_c for the reverse reaction?
Formula:
For reverse reaction 2NO₂(g) <=> N₂(g) + 2O₂(g), K_c' = 1/K_c = 1/0.01 = 100 ..
Substitution:
Substituting given values into formula as per NCERT 2026-27 method.
Calculation:
Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc.
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Discussion
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