Practice question
Question
For a reaction with Δ H = -120 kJ and Δ G = -130 kJ at 298 K, what is Δ S?
Explanation
Δ G = Δ H - TΔ S, -130 = -120 - 298 Δ S, Δ S = (-130 + 120) / -298 = 0.0336 kJ/K = 33.6 J/K.
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