Practice question

**Concave mirror image formation** depends on object position: beyond C real inverted diminished between F and C, at C real inverted same size at C, between C and F real inverted magnified beyond C, at F image at infinity, within F virtual erect magnified behind mirror. Focal length: f = -8 cm , u = -20 cm . Mirror equation: (1/v) + (1/-20) = (1/-8) ⇒ (1/v) = (1/-8) + (1/20) = (-5 + 2/40) = (-3/40) . v = -(40/3) ≈ -13.33 cm (real image). Substituting values gives 13.3 cm, which matches expected image position and magnification from mirror/lens formula 1/f = 1/v -