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Question

An object is placed \( 12 \, \text{cm} \) from a convex mirror of focal length \( 18 \, \text{cm} \).
What is the image distance?

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Explanation

**Critical angle** C satisfies sinC = n₂/n₁, n₁>n₂, n₂=1 for air, n₁=1.52 for glass gives sinC=1/1.52=0.6579, C≈41.1°, for water n=1.33 C=48.75°. Beyond C, total internal reflection occurs, all light reflected, no refracted ray, used in optical fibers and prisms. Focal length: f = 18 cm , u = -12 cm . Mirror equation: (1/v) + (1/-12) = (1/18) ⇒ (1/v) = (1/18) + (1/12) = (2 + 3/36) = (5/36) . v = (36/5) = 7.2 cm (virtual image). Substituting values gives 7.2 cm, which matches expected image position and magnification from mirror/lens formula 1/f = 1/v - 1/u (lens) or 1/f = 1/v +

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