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Question

An electromagnetic wave in vacuum has an electric field amplitude of \( 45 \, \text{V/m} \). What is
the magnetic field amplitude? (Given \( c = 3 \times 10^8 \, \text{m/s} \))

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Explanation

**Transverse nature** means E and B perpendicular to direction, e.g., wave propagating along z, E along x, B along y, Poynting vector S = E×B/μ₀ along z, energy flow direction. E and B in phase, maxima together, ratio fixed c. Using B₀ = (E₀/c) , we have B₀ = (45/3 × 10⁸) = 1.5 × 10⁻⁷ T . Using c = fλ, E₀/B₀ = c, I_d = ε₀ dΦ_E/dt, and spectrum classification λ = c/f, evaluation yields 1.5 × 10⁻⁷ T, illustrating EM wave transverse nature and Maxwell's displacement current concept.

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