Practice question
Question
A weak base BOH ( Kb = 2.0 × 10⁻⁵ ) has a 0.1 M solution with pH 10.5. What is the degree of ionization?
Explanation
pOH = 14 - 10.5 = 3.5 , [OH-] = 10⁻³.⁵ ≈ 3.16 × 10⁻⁴ , α = ([OH-]/[BOH]) = (3.16 × 10⁻⁴/0.1) = 3.16 × 10⁻³ = 0.00316 .
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