Practice question
Question
A wave \( y = 0.02 \sin (40x - 120t) \) reflects at an open boundary. What is the equation of the
reflected wave?
Explanation
**Reflection at boundaries** follows phase change rules: rigid boundary (fixed end) introduces π phase shift, inverting displacement y → -y, while free boundary reflects without phase change. Reflected wave derived by reversing propagation direction kx → -kx and applying phase shift, preserving k = 2π/λ and ω = 2πf. At open boundary, no phase change. Incident: y_i = 0.02 sin (40x - 120t) . Reflected: y_r = 0.02 sin (40x + 120t) . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields y = 0.02 sin (40x + 120t), illustrating frequency-length-speed interdependence and quantization by boundaries.
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