Practice question

MCQ

Question

A system at constant pressure releases 800 J of heat and contracts by 0.3 L against 2 atm. What is Δ U ? (1 atm·L = 101.325 J)

Options

Choose one · Correct answer highlighted

-800 J -739.2 J Correct -860.8 J -678.4 J

Explanation

Work done: w = -PΔ V = -2 × (-0.3) × 101.325 = 60.795 J . Given q = -800 J , Δ U = q + w = -800 + 60.795 = -739.21 ≈ -739.2 J .

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