Practice question

Given: A submarine window ( 0.03 m² ) is at 500 m depth in seawater ( rho = 1.03 × 10³ kg/m³ ). What force acts on it if inside pressure is atmospheric? (Take g = 10 m/s² ) These values define the system as per NCERT data. Formula: Gauge pressure: P_g = rho g h = 1.03 × 10³ × 10 × 500 = 5.15 × 10⁶ Pa. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: F = P_g A = 5.15 × 10⁶ × 0.03 = 1.545 × 10⁵ N . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.