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Practice question

MCQ

Question

A steel wire of length 2 m and cross-sectional area 2 × 10-6 m2 is stretched by a force of 200 N. If the Young's modulus of steel is 2 × 1011 N/m2, what is the elongation of the wire?

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Explanation

Using Young's modulus formula: Y = (F L) / (A ΔL). Rearrange for elongation: ΔL = (F L) / (A Y). Substitute values: ΔL = (200 × 2) / (2 × 10-6 × 2 × 1011). Calculate: ΔL = 400 / (4 × 105) = 10-3 m = 1 mm.

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