Practice question
Question
A spring (k\=500N/m) is stretched from 0.12m to 0.18m. What is the work done by the spring force?
Explanation
Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives -4.5 J. Work-energy theorem W=ΔK confirms. So option B is correct.
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