Practice question
Question
A solution is prepared by dissolving 15 g of a solute in water to make 250 mL of solution. If the osmotic pressure is 1.476 atm at 27°C, what is the molar mass of the solute? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
Pi = (w/M V) RT . 1.476 = (15/M × 0.25) × 0.0821 × 300 . M = (15 × 0.0821 × 300/1.476 × 0.25) ≈ 100 g/mol .
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