Practice question
Question
A solution is made by mixing 40 g of a solute (molar mass = 80 g/mol) with water. If the freezing point depression is 0.93°C and Kf = 1.86 K kg mol⁻¹ , what is the total mass of the solution?
Explanation
Moles = (40/80) = 0.5 . Δ Tf = Kf · m . 0.93 = 1.86 × (0.5/w) , w = (0.5 × 1.86/0.93) = 1 kg = 1000 g . Total mass = 40 + 1000 = 1040 g .
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