Practice question
Question
A solution contains 15 ppm of CaCl₂ by mass in water. What is its molality? (Molar mass: CaCl₂ = 111 g/mol)
Explanation
15 ppm = 15 g CaCl₂ in 10⁶ g water. Moles = 15 / 111 ≈ 0.1351 mol. Mass of solvent = 10⁶ g = 1000 kg. Molality = 0.1351 / 1000 ≈ 1.351 × 10⁻⁴ m.
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