Practice question
Question
A solenoid with 1000 turns per meter and current 2 A has a core with relative permeability μ_r = 200 . What is the magnetic field B inside?
Explanation
Given:
A solenoid with 1000 turns per meter and current 2 A has a core with relative permeability μ_r = 200 . What is the magnetic field B inside?
These values define the system as per NCERT data.
Formula:
Magnetic field B = μ_0 μ_r H, where H = n I.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Given: n = 1000 m^{-1, I = 2 A, μ_r = 200, μ_0 = 4Ï€ × 10â»â· T m A^{-1 . First, H = 1000 × 2 = 2000 A m^{-1 . Then, B = 4Ï€ × 10â»â· × 200 × 2000 = 0.5024 T approx 0.5 T .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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