Practice question
Question
A rectangular block of aluminium with dimensions 0.5 m × 0.2 m × 0.1 m is subjected to a shearing force of 6 × 104 N. If the shear modulus of aluminium is 2.5 × 1010 N/m2, what is the shear strain?
Explanation
Shear modulus: G = (Shear stress) / (Shear strain). Shear stress: Shear stress = F / A, A = 0.5 × 0.2 = 0.1 m2. So, Shear stress = (6 × 104) / 0.1 = 6 × 105 N/m2. Shear strain: Shear strain = Shear stress / G = (6 × 105) / (2.5 × 1010) = 2.4 × 10-5.
Discussion
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