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Question

A pipe open at both ends has a length of 0.75 m and a speed of sound of 330 m/s. What is the frequency
of its second harmonic?

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Explanation

**Organ pipe modes** illustrate boundary influence. Closed pipe odd harmonic series contrasts with open pipe full series, affecting timbre. Frequency scales inversely with length, explaining pitch variation with pipe length. For open pipe: v_n = (n v/2L) . Second harmonic ( n = 2 ): v₂ = (2 × 330/2 × 0.75) = (660/1.5) = 440 Hz . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 440 Hz, illustrating frequency-length-speed interdependence and quantization by boundaries.

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