Practice question
Question
A force F\=5i^+3j^N acts on a particle moving along a displacement d\=2i^+4j^m. What is the work done by the force?
Explanation
Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 22 J. Work-energy theorem W=ΔK confirms. So option C is correct.