Practice question
Question
A cylinder of mass 10kg and radius 0.5m rolls without slipping. If its angular momentum about its axis is 25kg m2/s, what is its angular velocity?
Explanation
Angular momentum: L = Iω. For a solid cylinder: I = 12MR2 = 12×10×(0.5)2 = 1.25kgm2. ω = LI = 251.25 = 20rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 20 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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