Practice question
Question
A cross was made between wild type female Drosophila melanogaster and mutant males which are yellow bodied (y) and crossveinless (cv). The two genes are present on the X-chromosome. The F₁progeny was sib-mated and the observation of F₂progeny is tabulated below. With regard to the above analysis, which one of the following statements is correct?
Explanation
Analysis of a cross was made between wild type shows If the mapping was done with a 3ʳᵈ marker which lies between represents established outcome. functional assays supports option B, whereas distractors confuse substrate or regulatory direction and fail to reproduce observed results.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.