Skip to content

Question

A conducting loop is moved out of a magnetic field region. The induced current flows to oppose what
specific change?

Options

Choose one · Correct answer highlighted

Explanation

**Flux change example** coil 150 turns area 0.06 m² B 0.14 T drops to zero in 0.3 s, ΔΦ = B A =0.14×0.06=0.0084 Wb per turn, ΔΦ/Δt=0.028 Wb/s, e=150×0.028=4.2 V, illustrating calculation from B and area. Moving the loop out reduces the magnetic flux through it, and the induced current opposes this decrease by generating a field in the same direction as the original field. Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I², result Decrease in

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.