Practice question

Given: A compound has an empirical formula C₂H₃O₂ and a molar mass of 118 g/mol. What is its molecular formula? (Atomic masses: C = 12, H = 1, O = 16) These values define the system as per NCERT data. Formula: Empirical mass = (2 × 12) + (3 × 1) + (2 × 16) = 24 + 3 + 32 = 59 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: n = 118 / 59 = 2. Molecular formula = C₄H₆O₄. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.