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Question

A capillary tube of radius 0.15mm is dipped in water (S\=0.0727N/m, ρ\=1000kg/m3, cos⁡θ\=1). What is the capillary rise? (Take g\=9.8m/s2)

Options

Choose one · Correct answer highlighted

Explanation

h = 2Scos⁡θρga. S = 0.0727N/m, ρ = 1000kg/m3, g = 9.8m/s2, a = 0.15×10−3m. h = 2×0.0727×11000×9.8×0.15×10−3 = 0.0989m = 9.89cm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9.9 cm. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

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