Practice question

Given: A bubble of radius 5.5 mm is blown at 45 cm depth in water ( rho = 1000 kg/m³, S = 0.0727 N/m ). What is the total pressure inside? (Take P_a = 1.01 × 10⁵Pa, g = 10 m/s² ) Formula: P_i = P_a + rho g h + 2 S/r. Substitution & Calculation: P_a = 1.01 × 10⁵Pa, rho g h = 1000 × 10 × 0.45 = 4500 Pa . 2 S/r = frac2 × 0.07275.5 × 10⁻³= 26.44 Pa . P_i = 1.01 × 10⁵+ 4500 + 26.44 = 1.05526 × 10⁵Pa . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.