Practice question
Question
A brass wire of length 2.4m and cross-sectional area 3×10−6m2 is stretched by a force producing a stress of 5×107N/m2. If the Young's modulus of brass is 9×1010N/m2, what is the strain?
Explanation
Young's modulus: Y = StressStrain. Strain: Strain = StressY = 5×1079×1010≈5.56×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.56×10−4. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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