Practice question
Question
A ball is thrown upwards at 18m/s from a 32m tower. What is its speed when it passes the tower’s base on the way down? (Take g\=10m/s2)
Explanation
v2=v02+2gh, v2=(18)2+2⋅10⋅32=324+640=964. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 30 m/s as the result, so option A is correct.