Practice question
Question
A \( 5 \, \Omega \) resistor carries a current of \( 4 \, \text{A} \) for \( 15 \, \text{s} \). What is
the energy dissipated?
Explanation
**Current and drift relation** I = n e A v_d shows current proportional to drift velocity and area. For A=6×10⁻⁷ m², I=1.8 A, n=8.5×10²⁸ m⁻³, v_d =1.8/(8.5×10²⁸×1.6×10⁻¹⁹×6×10⁻⁷)=2.2×10⁻⁴ m/s, illustrating small drift speed even for ampere currents. Energy: W = I² R t . Substitute: W = 4² × 5 × 15 = 16 × 75 = 1200 J . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 1200 J,
Discussion
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